Benutzer:WITTus/übungen

${\frac {4}{x-4}}-{\frac {2}{x-3}}={\frac {14}{x(x-7)+12}}$

${\frac {4(x-3)-2(x-4)}{(x-4)*(x-3)}}={\frac {14}{x^{2}-7x+12}}$

${\frac {4x-12-2x+8}{x^{2}-3x-4x+12}}={\frac {14}{x^{2}-7x+12}}$

${\frac {2x-4}{x^{2}-7x+12}}={\frac {14}{x^{2}-7x+12}}$

$2x-4=14$

$2x=18$

$x=9$

${\frac {x*2}{x^{2}*4}}+{\frac {2x*4}{(x+2)^{2}}}={\frac {7}{(x+2)^{2}}}$